Find the equation of the parabola that satisfies the given conditons:
Focus
Vertex (0,0); Focus (3,0)

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Solution

The vertex of the parabola is at (0,0) and focus is at (3,0).
$∴ y = 0 \Rightarrow$ The axis of parabola is along x-axis
So the parabola is of the form $y^{2} = 4 a x$ .
The required equation of parabola is,
$y^{2} = 4 \times 3 x \Rightarrow y^{2} = 12 x .$

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Find the equation of the parabola that satisfies the given conditons: Focus Vertex (0,0); Focus (3,0)

The vertex of the parabola is at (0,0) and focus is at (3,0). ∴y=0⇒ The axis of parabola is along x-axis So the parabola is of the form y2=4ax. The required equation of parabola is, y2=4×3x⇒y2=12x.

Find the equation of the parabola that satisfies the given conditons:
Focus
Vertex (0,0); Focus (3,0)

The vertex of the parabola is at (0,0) and focus is at (3,0).
$∴ y = 0 \Rightarrow$ The axis of parabola is along x-axis
So the parabola is of the form $y^{2} = 4 a x$ .
The required equation of parabola is,
$y^{2} = 4 \times 3 x \Rightarrow y^{2} = 12 x .$