Find the equation of the plane containing two parallel lines x-12-y-1-1-z3 and x4-y-2-2-z-16- Also- find if the plane thus obtained contains the line x-23-y-11-z-25 or not-

[ Let; L_ 1 : x 1 2 = y+1 1 = z 3 #160;; L_ 2 : x 4 = y 2 2 = z+ ...

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Condition for Coplanarity of Four Points

Find the equa...

Question

Find the equation of the plane containing two parallel lines $\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z}{3}$ and $\frac{x}{4} = \frac{y - 2}{- 2} = \frac{z + 1}{6}$ . Also, find if the plane thus obtained contains the line $\frac{x - 2}{3} = \frac{y - 1}{1} = \frac{z - 2}{5}$ or not.

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\frac{x + 3}{- 3} = \frac{y - 1}{1} = \frac{z - 5}{5}; \frac{x + 1}{- 1} = \frac{y - 2}{2} = \frac{z - 5}{5}

\frac{x - 2}{1} = \frac{y - 4}{4} = \frac{z - 6}{7}

\frac{x + 1}{3} = \frac{y + 3}{5} = \frac{z + 5}{7}

\frac{x - 1}{3} = \frac{y - 6}{4} = \frac{z - 1}{2}

\frac{x - 2}{2} = \frac{y - 1}{- 3} = \frac{z + 4}{3}

\frac{x}{4} = \frac{y}{2} = \frac{z}{1}

\frac{x - 4}{1} = \frac{y - 5}{4} = \frac{z - 9}{2}

\frac{x + 8}{4} = \frac{y + 6}{2} = \frac{z - 2}{1}

\frac{x - 2}{2} = \frac{y - 2}{2} = \frac{z - 1}{3}

\frac{x + 1}{3} = \frac{y - 1}{2} = \frac{z + 1}{1}

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