wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of the plane passing through the point (1,1,2) and perpendicular to the planes 2x+3y3z=2 and 5x4y+z=6.

Open in App
Solution

Let the equation of the plane containing the given point (1,1,2) is
A(xx1)+B(yy1)+C(zz1)=0(i.e)A(x1)+B(y+1)+C(z2)=0

Applying the condition of perpendicular to the plane in equation (1) with the plane
2x+3y2z=5 and x+2y3z=8

We have, 2A+3B2C=0 and A+2B3C=0

Let us solve three two equations, we get
A=5C
B=4C

The required equation is
5C(x1)+4C(y+1)+c(z2)=05x4yz7=05x4yz=7

Hence, this is the answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Altitude of a triangle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon