Question

Find the equation of the plane which makes intercepts $1,-1$ and $2$ on the $x,y$ & $z$ axes respectively.

Answer 1

equation of a plane in intercept form : $\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1$

$x-intercept=1$

$y-intercept=-1$

$z-intercept=2$

equation of the plane = $\frac{x}{1}+\frac{y}{-1}+\frac{z}{2}=1$

$x-y+\frac{z}{2}=1$

$2x-2y+z=2$