Find the equation of the plane which passes through the point 2^i+3^j−^k and perpendicular to the vector 3^i−2^j−2^k. Also find the perpendicular distance of this plane from the origin.
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Solution
Assume that the equation of normal to plane is →n=a^i+b^j+c^k and the point on plane is of form →p=x0^i+y0^j+z0^k
Hence, equation of plane with normal →n and passing through point →p is a(x−x0)+b(y−y0)+c(z−z0)=0