Find the equation of the straight line equally inclined to the lines, $3 x = 4 y + 7$ and $5 y = 12 x + 6$ .

Open in App

Solution

Equation of angular bisector will be $\frac{3 x - 4 y - 7}{5} = \pm \frac{12 x - 5 y + 6}{13}$
$⟹ (39 x - 52 y - 91) = \pm (60 x - 25 y + 30)$
$⟹ 21 x + 27 y + 121 = 0, 99 x - 77 y - 61 = 0$

Suggest Corrections

Similar questions

(4, 5)

3 x = 4 y + 7

5 y = 12 x + 6

Equation of a straight line passing through the point $(4, 5)$ and equally inclined to the lines $3 x = 4 y + 7$ and $5 y = 12 x + 6$ is

Find the equation of the line which pass through $(4, 5)$ and makes equal angles with the lines $5 y = 12 x + 6$ and $3 x = 4 y + 7$ .

3 x = 4 y + 7

5 y = 12 x + 6

(4, 5)

3 x - 4 y + 7 = 0

12 x - 5 y - 8 = 0

Join BYJU'S Learning Program