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Question

Find the equation of the straight line parallel to the line 3x−y+7=0 and passing through the point (1,−2).

A
3xy5=0
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B
3x+y5=0
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C
3xy+5=0
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D
None of these
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Solution

The correct option is A 3xy5=0
Consider the given equation.
3xy+7=0 ...........(1)

slope=31=3

Since, the line is parallel to given line. so slope will be same.
slope=3

We know that the equation of the line which is passing through the point
yy1=slope(xx1)

So,
y+2=3(x1)

y+2=3x3

3xy5=0

Hence, this is the answer.

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