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Question

Find the equation of the straight line passing through the pair of points (a, b) and (a + b, a-b).

A
(2ba)x+by+(a2b22ab)=0
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B
(2ab)x+by+(a2b22ab)=0
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C
(2ba)x+ay+(a2b22ab)=0
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D
(2ab)x+by+(a2b22b)=0
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Solution

The correct option is A (2ba)x+by+(a2b22ab)=0
Points are (a, b) and (a + b, a - b)
So, equation of line be, yb=abba+ba(xa)yb=a2bb(xa),b(yb)=(a2b)(xa)byb2=axa22bx+2abbyb2ax+a2+2bx2ab=0(2ba)x+by+(a2b22ab)=0

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