Find the equation of the straight line passing through the point $(- 2, 3)$ with slope $\frac{1}{3}$ .

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Solution

Given that the slope $m = \frac{1}{3}$ and a point $(x_{1}, y_{1}) = (- 2, 3)$
By slope point formula, the equation of the straight line is
$y - y_{1} = m (x - x_{1})$
$\Rightarrow$ $y - 3 = \frac{1}{3} (x + 2)$
Thus, $x - 3 y + 11 = 0$ is the required equation.

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