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Question

Find the equation of the straight line passing through the point (−2,5) and (3,6)

A
x5y+27=0
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B
x+5y+27=0
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C
x5y27=0
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D
None of these
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Solution

The correct option is A x5y+27=0
Consider the given points.
(2,5) and (3,6)

We know that the equation of the line which is passing through the points
yy1=y2y1x2x1(xx1)

So,
y5=653+2(x+2)

y5=15(x+2)

5y25=x+2

x5y+27=0

Hence, this is the answer.

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