Question

Find the equation of the straight line passing through the point $(-2,5)$ and $(3,6)$

• A. $x-5y+27=0$
• B. $x+5y+27=0$
• C. $x-5y-27=0$
• D. None of these

Answer 1

The correct option is A $x-5y+27=0$

Consider the given points.

$(-2,5)$ and $(3,6)$

We know that the equation of the line which is passing through the points

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

So,

$y-5=\frac{6-5}{3+2}(x+2)$

$y-5=\frac{1}{5}(x+2)$

$5y-25=x+2$

$x-5y+27=0$

Hence, this is the answer.