Question

Find the equation of the straight line passing through the point $(4,-3)$ and perpendicular to the line passing through the points $(1,1)$ and $(2,3)$.

Answer 1

Slope of line whose two points are given is

$m=\frac{3-1}{2-1}=2$

This is Perpendicular to required line

So, Slope of required line is $\frac{-1}{2}$

Hence, Equation is $y-(-3)=\frac{-1}{2}(x-4)\Rightarrow 2y+6=-x+4\Rightarrow x+2y+2=0$