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Question

~~Find the equation of the straight line passing through the point of intersection of the two lines x+2y+3=0 and 3x+4y+7=0 and parallel to the straight line y-x=8

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Solution

Dear student
x+2y+3=0 ...13x+4y+7=0 ...2 On solving the above equations we getx=-1 and y=-1Point of intersection of x+ 2y+3=0 and is -1,-1The equation of line parallel to the straight line y-x-8=0 is y-x+k=0-1+1+k=0k=0the required equation of the straight line is y-x=0

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