wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of the straight line passing through the point of intersection of the lines 2x+y−3=0 and 5x+y−6=0 and parallel to the line joining the points (1,2) and (2,1)

A
x+y2=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x+y+2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
xy2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x+y2=0
Consider the given equation of the line.
2x+y3=0 ...........(1)

5x+y6=0 ...........(2)

(2)(1)

5x2x+yy6+3=0

3x3=0

x=1 sun in (1)

2(1)+y3=0

y1=0

y=1

Point of intersection of above both lines is
=(1,1)

Given points
A(1,2),B(2,1)

Slope of AB=1221=11=1

Since, the line is parallel to the the line AB, so the slope must be equal.

So, the equation of line passes through intersection point
y1=1(x1)

y1=x+1

x+y2=0

Hence, this is the answer.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Straight Line
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon