Question

Find the equation of the straight line that has y - intercept 5 and is parallel to the straight line x - 3y = 3

• A. 3x - y + 5 = 0
• B. x - y +5=0
• C. x - 3y + 15 =0
• D. 2x - 3y +12 = 0

Answer 1

The correct option is C

x - 3y + 15 =0

Given line $x-3y=3$

Expressing the lines in $y=mx+c$ format

$3y=x-3$

$y=\frac{x}{3}-1$

Comparing this line with $y-mx+c$.

slope of the line $m=\frac{1}{3}$

Slope of the parallel line $m=\frac{1}{3}$

Equation of the line with slope $\frac{1}{3}$ and y intercept 5 is

$y=mx+c$

$y=\frac{1}{3}x+5$

$3y=x+15$

$x-3y+15=0$