Question

Find the equation of the straight line that has y - intercept 5 and is parallel to the straight line x - 3y = 3

• A. 3x - y + 5 = 0
• B. x - y +5=0
• C. x - 3y + 15 =0
• D. 2x - 3y +12 = 0

Answer 1

The correct option is C

x - 3y + 15 =0

Given line x-3y=3
Expressing the lines in y =mx+c format
3y=x-3
$y=\frac{x}{3}-3$
Comparing this line with y-mx+c. slope of the line $m=\frac{1}{3}$
Slope of the parallel line $m=\frac{1}{3}$
Equation of the line with slope $\frac{1}{3}$ and y intercept 5 is
y=mx+c
$y=\frac{1}{3}x+5$
3y=x+5
x-3y+5=0