Find the equation of the straight line which passes through the point (1, 2) and makes such an angle with the positive direction of x-axis whose sine is $\frac{3}{5} .$

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Solution

$L e t s i n θ = \frac{3}{4} T h e n, \Rightarrow m = s l o p e = t a n θ = \frac{3}{4} The equation of straight line with slope m and passing through (1, 2) is y y - y_{1} = m (x - x_{1}) y - 2 = \frac{3}{4} (x - 1) 4 y - 8 = 3 x - 3 3 x - 4 y = - 5 3 x - 4 y + 5 = 0$

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