Find the equation of the straight line whose slope is $- 4$ and passing through $(1, 2)$

4 x + y - 6 = 0

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4 x + y + 6 = 0

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4 x - y - 6 = 0

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None of these

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Solution

The correct option is A $4 x + y - 6 = 0$
We have,
$s l o p e = - 4$ and $p o i n t s (1, 2)$

We know that the equation of the line which is passing through the points
$y - y_{1} = s l o p e (x - x_{1})$

So,
$y - 2 = - 4 (x - 1)$

$y - 2 = - 4 x + 4$

$4 x + y - 6 = 0$

Hence, this is the answer.

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