Find the equation of the straight line whose x and y intercepts are $- \frac{2}{7}$ and $\frac{3}{5}$

Open in App

Solution

$\begin{matrix} e q u a t i o n s t r a i g h t l i n e \Rightarrow \frac{x}{a} + \frac{y}{b} = 1 h e n c e \frac{x}{- \frac{2}{7}} + \frac{y}{\frac{3}{5}} = 1 - \frac{7 x}{2} + \frac{5 y}{3} = 1 \end{matrix}$

Suggest Corrections

Similar questions

If the x-intercept and y-intercept of a straight line are 3/2 and 4/3 respectively, then find the equation of the straight line.

Q. Find the equation of the straight line whose

x

and

y

-intercepts on the axes are given by

2

and

3

If the x-intercept and y-intercept of a straight line are $\frac{3}{2}$ and $\frac{4}{3}$ respectively, then find the equation of the straight line.

Q. Find the equation of a straight line whose slope is

3

and

y

intercept is

5

Solve the following:
(a) Express x in terms of y for the equation 7x + 5y = 35 and find the X-intercept.
(b) Find the intercepts of the line whose equation is x + y = 4 [3 MARKS]

Join BYJU'S Learning Program

Find the equation of the straight line whose x and y intercepts are −27 and 35

equationstraightline⇒xa+yb=1hencex−27+y35=1−7x2+5y3=1

Find the equation of the straight line whose x and y intercepts are $- \frac{2}{7}$ and $\frac{3}{5}$

$\begin{matrix} e q u a t i o n s t r a i g h t l i n e \Rightarrow \frac{x}{a} + \frac{y}{b} = 1 h e n c e \frac{x}{- \frac{2}{7}} + \frac{y}{\frac{3}{5}} = 1 - \frac{7 x}{2} + \frac{5 y}{3} = 1 \end{matrix}$