Find the equation of the tangents at the ends of the latus rectum of the ellipse x2a2+y2b2=1 and also show that they pass through the points of intersection of the major axis and directions
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Solution
S:x2a2+y2b2=1
Ends of latus rectum are (ae,b2a),(ae,−b2a)
Equation of tangents will be S1=0
aexa2+b2yab2=1⟹ex+y=a
aexa2−b2yab2=1⟹ex−y=a
The points of intersection will be (ae,0)
⟹ they pass through the points of intersection of the major axis and directrix.