Find the equation of the tangents to the circle $x^{2} + y^{2} = 9$ which make an angle of $60^{\circ}$ with the x-axis.

Open in App

Solution

$E q u a t i o n o f t a n g e n t : y = m x + a \sqrt{m^{2} + 1} . \Rightarrow y = m x + 3 \sqrt{m^{2} + 1} . m = t a n 60 = \sqrt{3} . \Rightarrow y = \sqrt{3} x + 3 \sqrt{3 + 1} \Rightarrow y = \sqrt{3} x + 3 \times 2 \Rightarrow y = \sqrt{3 x} + 6.$

Suggest Corrections

Similar questions

x^{2} + y^{2} = 4

60^{o}

x

x^{2} + y^{2} - 6 x - 4 y + 5 = 0

45^{o}

x^{2} + y^{2} - 6 x - 4 y + 5 = 0

45^{o}

x -

\frac{x^{2}}{16} + \frac{y^{2}}{9} = 1

60^{o}

x^{2} + y^{2} = 9

\frac{π}{3}

x

Join BYJU'S Learning Program