Question

Find the equation of the x line parallel to the y-axis and drawn through the point of intersection of the lines $x-7y+5=0$ and $3x+y-7=0$

Answer 1

The equation of any line through the point of intersection of the given lines is of the form x=a.

$x-7y+5$ + k ($3x+y-7)=0$

$\Rightarrow (1+3k)x+(k-7)y+(5-7k)=0$

If the line is parallel to y-axis then coefficient of y should be 0, i.e., k -7 = 0, which given k = 7

Substituting k = 7 in (i), we get: 22x - 44 = 0

$\therefore x-2=0,$ which is the required equation.