Find the equation of trajectory of projectile projected at an angle 60 and has an initial velocity of 2 $m s^{- 1}$ .

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Solution

The correct option is A
$u = 2 m s^{- 1}, θ = 60^{0} ∴ Y = t a n θ x - \frac{g}{2 u^{2} c o s^{2} θ} x^{2} = \sqrt{3} x - 5 x^{2}$

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Find the equation of trajectory of projectile projected at an angle 60 and has an initial velocity of 2 ms−1.

The correct option is A u=2m s−1,θ=600∴Y=tan θx−g2u2 cos2θx2=√3x−5x2

Find the equation of trajectory of projectile projected at an angle 60 and has an initial velocity of 2 $m s^{- 1}$ .

The correct option is A
$u = 2 m s^{- 1}, θ = 60^{0} ∴ Y = t a n θ x - \frac{g}{2 u^{2} c o s^{2} θ} x^{2} = \sqrt{3} x - 5 x^{2}$