Question

Find the equation to the parabola whose focus is $(1,-1)$ and vertex is $(2,1)$

Answer 1

$Y^2=4AX$

$(\frac{2x+y-4}{\sqrt{5}}{)}^2=4\left(\sqrt{(2-1{)}^2+(1+1{)}^2}\right)(\frac{y-2x+3}{\sqrt{5}})⟹(2x+y-4{)}^2=20(y-2x+3)$