3x−4y=35........(i)2x+5y=8⇒x=8−5y2
substituting x in (i)
3(8−5y2)−4y=3524−15y−8y=70−23y=46⇒y=−2x=8−5(−2)2⇒x=9
So the point of intersection is P(9,−2)
Equation of line joining (2,−9) and P is
y−(−2)=(−9−(−2)2−9)(x−9)y+2=−7−7(x−9)y+2=x−9x−y=11
The equation of the straight line passing through the point of intersection of lines 3x – 4y – 7 = 0 and 12x – 5y – 13 = 0 and perpendicular to the line 2x – 3y + 5 = 0 is