Question

Find the equation to the straight line which passes through point of intersection of line $2x+y+1=0$ & $3x-y+4=0$ and is parallel to line $3x-2y=0$.

• A. $3x-2y=-5$.
• B. $3x-2y=1$.
• C. $3x-2y=-8$.
• D. $x-y=-5$.

Answer 1

The correct option is A $3x-2y=-5$.

Given equation of the lines

$2x+y+1=0$......(1)

$3x-y+4=0$.....(2).

Now adding (1) and (2) we get,

$5x=-5$

or, $x=-1$.

Now putting the value of $x=-1$ in (1) we get, $y=1$.

Now the line parallel to the line $3x-2y=0$ is $3x-2y=c$......(3) [ Where $c$ is the integrating constant].

According to the problem, line (3) passing through $(-1,1)$ then $c=-5$.

So the required equation of the line is $3x-2y=-5$.