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Question

Find the equation whose roots are the reciprocals of the roots of 3x25x+7=0

A
7x25x+3=0
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B
7x2+5x+3=0
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C
4x25x+3=0
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D
7x25x+7=0
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Solution

The correct option is B 7x25x+3=0
α+β=ba=53 & αβ=73
Reciprocal roots are 1α& 1β
1α+1β=α+βαβ=57 & (1α1β)=37
eqn is x2(1α+1β)x+1αβ=0
x257x+37=0
7x25x+3=0

1117825_528844_ans_0b5f9a07618b4346978e16a81b180e12.jpg

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