Find the equations of tangents to the parabola y2=12x which make an angle of 45∘ with the line y=3x+7.
A
x−2y+12=0
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B
x+2y+12=0
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C
4x+2y+3=0
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D
4x−2y−3=0
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Solution
The correct options are Ax−2y+12=0 C4x+2y+3=0 tan(±45∘)=M−31+3M⇒M=−2,12 or m=3,t=tanα=tan45∘=1 ∴M=m−t1+mt and m+t1−mt or 12,−2 x−2y+12=0,4x+2y+3=0 Ans: A,C