Find the equations of the circle that passes through the points (0, 6), (0, 0) and (8, 0).

(x - 4)^{2} + (y - 3)^{2} = 25

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(x - 3)^{2} + (y - 4)^{2} = 25

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(x - 3)^{2} + (y - 3)^{2} = 25

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None of these

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Solution

The correct option is B
$(x - 4)^{2} + (y - 3)^{2} = 25$

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Similar questions

(x - 4)^{2} + (y + 3)^{2} = 25

(x - 3)^{2} + (y + 4)^{2} = 25

x^{2} + y^{2} - 4 x + 6 y + 10 = 0

4 x - 3 y + 8 = 0

{(x + 3)}^{2} + {(y - 4)}^{2} = 25

\sqrt{(x + 4)^{2} + (y - 3)^{2}} - \sqrt{(x - 4)^{2} + (y - 3)^{2}} = 6

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