Question

Find the equations of the lines for which $\tan \theta =\frac{-2}{3},$ where $\theta$ is the angle of inclination of the line and $x-$intercept is $3$

Answer 1

$x-$intercept is $3$

Using slope intercept form, the equation of the line is $y=m(x-d)$

$y=\frac{-2}{3}(x-3)$

$\Rightarrow 3y=-2x+6$

$\therefore$ equation of the line is $2x+3y-6=0$