Find the equations of the lines passing through point (-2, 0) and equally inclined to the co-ordinate axes.
xa+yb=1............(1)
Now, we have to find the equation which is equally inclined to the co-ordinate axes.
Hence put a=b in equation (1),
xa+ya=1⇒x+ya=1⇒x+y=a...(2)
Put the points (−2,0) we get,
−2+0=a⇒a=−2
Again put value of a in equation (2),
x+y=−2
Or
x+y+2=0