Find the equations of the straight lines which cut off an intercept 5 from the y-axis and are equally inclined to the axes.
It is given that the lines are equally inclined to the axes.So, their inclinations with the positive x-axis are 45∘ and 135∘
Let m1 and m2 be the slopes of the lines.∴ m1=tan 45∘=1 and m2=tan 135∘=tan 45∘=−1Thus, the equations of the lines passing through (0, 5) with slopes 1 and -1 arey−5=1(x−0) and y−5=−1(x−0)⇒ y−x−5=and y+x−5=0⇒ y=x+5 and x+y=5