Find the equations of the tangents to the hyperbola $x^{2} - 3 y^{2} = 9$ which are parallel to the line $y = 3 x + 5.$

2 x - y \pm 2 \sqrt{6} = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x - y \pm 2 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - y \pm 2 \sqrt{6} = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x - y \pm 2 \sqrt{6} = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $3 x - y \pm 2 \sqrt{6} = 0$
Slope of tangent is $m = 3$
Then equation of tangent is $y = m x \pm \sqrt{a^{2} m^{2} - b^{2}}$
$\Rightarrow y = 3 x \pm 2 \sqrt{6}$

Suggest Corrections

Similar questions

3 x^{2} - 4 y^{2} = 12

2 x^{2} - 3 y^{2} = 6

y = 3 x + 4

2 x^{2} - 3 y^{2} = 6

x^{2} + y^{2} - 2 x + 6 y - 6 = 0

3 x - 4 y + 7 = 0

3 x - 4 y + k = 0

What is the equation of tangent to the hyperbola
$2 x^{2} - 3 y^{2} = 6$ which is parallel to the line $y = 3 x + 4$ , is

Join BYJU'S Learning Program