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Question

Find the equations to the common tangents of the parabolas y2=4axandx2=4by

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Solution

Equation of tangent to y2=4ax is

y=mx+am...............(i)

Equation of tangent to x2=4by is

x=m1y+bm1y=1m1xb(m1)2............(ii)

for common tangent (i) & (ii) must represent the same line

1m1=m&am=bm21
am=bm2m=(ab)13

equation of common tangent is
y=(ab)13x+a(ba)13

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