Question

Find the equivalent capacitance across A and B for the arrangement shown in the figure. All capacitors are of capacitance C.

• A. 3C/14
• B. C/8
• C. 3C/16
• D. none of these

Answer 1

The correct option is A 3C/14

Since $C_9$ is shorted so $C_1,C_2,C_3,C_4,C_5$ are in series

Equivalent capacitance is $C_x=\frac{C}{5}$

$C_6,C_7$ are in series and the combination is parallel to $C_{10}$

Resultant Capacitance is $C_y=C+\frac{C}{2}=\frac{3C}{2}$

Now $C_x,C_y,C_8$ are in series

The equivalent capacitance for the combination is $\frac{1}{C_{eq}}=\frac{1}{C}\times (5+\frac{2}{3}+1)=\frac{14}{3C}$

$\therefore C_{eq}=\frac{3C}{14}$