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Question

Find the equivalent capacitance between points A and B.


A
209 μF
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B
9 μF
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C
2 μF
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D
265 μF
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Solution

The correct option is B 9 μF
Redrawing the given circuit, we can see that all the branches containing capacitors are in parallel (connected between point A and B).

Ceq=6×36+3+3+4

Ceq=2μF+3 μF+4 μF

Ceq=9 μF

Hence, option (b) is correct.

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