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B
r
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C
r2
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D
r3
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Solution
The correct option is A2r3 Given circuit is symmetrical about the line 123 and it is perpendicular to AB.
So, due to the perpendicular axis symmetry, point 1, 2 and 3 are equipotential. So resistors between them can be removed since current will not flow through them.
Now, the resistors between A−1 and 1−B are in series. Their equivalent resistance will be r+r=2r. Similarly resistors A−2, 2−B and A−3, 3−B have equivalent resistance 2r.
Now all three are in parallel combination. Their equivalent resistance will be, RAB=2r3