Question

Find the equivalent resistance of the circuit, if resistance of each resistor is $4\Omega$.

• A. $2\Omega$
• B. $6\Omega$
• C. $8\Omega$
• D. $4\Omega$

Answer 1

The correct option is B $6\Omega$

Given:
Resistance of each resistor is $4\Omega$.

Resistors 2 and 3 are in parallel.
Therefore, equivalent resistance,
$\frac{1}{R_{net}}=\frac{1}{R_2}+\frac{1}{R_3}$
$\frac{1}{R_{net}}=\frac{1}{4}+\frac{1}{4}$
$⟹R_{net}=2\Omega$

Now, $R_{net}$ is in series with $R_1$.
$R_{total}=R_1+R_{net}$
$R_{total}=2+4=6\Omega$