1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard IX
Mathematics
Introduction to Algebraic Identities
Find the expa...
Question
Find the expansion of
(
2
x
+
3
)
(
2
x
−
5
)
(
2
x
−
7
)
A
8
x
3
−
36
x
2
−
2
x
+
105
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
8
x
3
+
36
x
2
−
2
x
+
105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8
x
3
−
36
x
2
+
2
x
+
105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
8
x
3
−
36
x
2
−
2
x
+
105
(
2
x
+
3
)
(
2
x
−
5
)
(
2
x
−
7
)
=
(
4
x
2
−
10
x
+
6
x
−
15
)
(
2
x
−
7
)
=
(
4
x
2
−
4
x
−
15
)
(
2
x
−
7
)
=
8
x
3
−
28
x
2
−
8
x
2
+
28
x
−
30
x
+
15
=
8
x
3
−
36
x
2
−
2
x
+
105
Suggest Corrections
0
Similar questions
Q.
Solve the equation
8
x
3
−
36
x
2
−
18
x
+
18
=
0
the root being in A.P
Q.
If
2
x
−
1
2
x
=
4
;
f
i
n
d
:
(
i
)
4
x
2
+
1
4
x
2
(
i
i
)
8
x
3
−
1
8
x
3
Q.
Expand:
(
(
2
x
−
1
)
2
)
2
−
36
x
2
Q.
If
x
≠
0
and
2
x
+
1
2
x
=
21
. Find the value of
8
x
3
+
1
8
x
3
[4 MARKS]
Q.
If
x
≠
0
and
2
x
+
1
2
x
=
21
. Find the value of
8
x
3
+
1
8
x
3
[4 MARKS]
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
(a + b)²
MATHEMATICS
Watch in App
Explore more
Introduction to Algebraic Identities
Standard IX Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app