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Question

Find the expansion of (3x22ax+3a2)3.

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Solution

(3x22ax+3a2)3

=(3a2)3{1+3x22ax3a2}3
=27a6{3C0+3C1(3x22ax3a2)+3C2(3x22ax3a2)2+3C3(3x22ax3a2)3} ...... Using binomial expansion
=27a654a5x+117a4x2116a3x3+117a2x454ax5+27x6

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