Find the expansion of the following:
$(6 - 4 a - 7 b)^{2}$

Open in App

Solution

$(6 - 4 a - 7 b)^{2}$
Let us simplify the expression, we get
$(6 - 4 a - 7 b)^{2} = [6 + (- 4 a) + (- 7 b)]^{2}$
$= (6)^{2} + (- 4 a)^{2} + (- 7 b)^{2} + 2 (6) (- 4 a) + 2 (- 4 a) (- 7 b) + 2 (- 7 b) (6)$
$= 36 + 16 a^{2} + 49 b^{2} - 48 a + 56 a b - 84 b$

Suggest Corrections

Similar questions

\frac{3 a + 7 b}{3 a - 7 b} = \frac{4}{3}

\frac{3 a^{2} - 7 b^{2}}{3 a^{2} + 7 b^{2}}

{(4 a - 7 b)}^{2} - {(3 a)}^{2}

(x - a) (x - 2 a) (x - 4 a)

\frac{3 a + 7 b}{3 a - 7 b} = \frac{4}{3}

\frac{3 a^{2} - 7 b^{2}}{3 a^{2} + 7 b^{2}}

\frac{3 a + 7 b}{3 a - 7 b} = \frac{4}{3}

\frac{3 a^{2} - 7 b^{2}}{3 a^{2} + 7 b^{2}}

Join BYJU'S Learning Program