Question

Find the exponent of the first term in $\sqrt{y^3}+y^2$

• A. $2$
• B. $1$
• C. $3$
• D. $\frac{3}{2}$

Answer 1

The correct option is D $\frac{3}{2}$

$\sqrt{y^3}+y^2$$=y^{\frac{3}{2}}+y^2$

Therefore, the exponent is $\frac{3}{2}$.