Question

Find the exponent of the second term in $3\sqrt{y}+y^2$.

• A. $1$
• B. $2$
• C. $3$
• D. $\frac{3}{2}$

Answer 1

Answer: (B)

$2$

$3\sqrt{y}+y^2$$=3y^{\frac{1}{2}}+y^2$

Therefore, the exponent of the second term is is $2$.