Question

Find the exponent $(?)$ to the base $10$ in the following: $72.3\times {10}^{?}=72.3$

• A. $1$
• B. $0$
• C. $2$

Answer 1

The correct option is B $0$

$\underset{–}{\text{Need to find:}}$ The exponent $(?)$ in $72.3\times {10}^{?}=72.3$

We know that multiplying $72.3$ by $1$ gives the same number $72.3$, i.e., $72.3\times 1=72.3$.

$\underset{–}{\text{Note:}}$ $1$ is always a non-zero number with $0^{\text{th}}$ power.

We can write $1$ as ${10}^0$.

$\therefore 72.3\times 1=72.3\times {10}^0=72.3$

Hence, the exponent $(?)$ in $72.3\times {10}^{?}=72.3$ is $\underset{–}{0}$.