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Question

# Find the expression for electric potential at a point P located on the central perpendicular axis of a uniformly charged ring of radius a and total charge Q, at a distance of x from the centre.

A
Q4πϵ0x
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B
Q4πϵ0(x2a2)
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C
Q4πϵ0a
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D
Q4πϵ0(x2+a2)
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Solution

## The correct option is D Q4πϵ0√(x2+a2)Let us consider an element of charge dq.Potential at P due to this charge element is given by-dV=dq4πϵorEvery point on ring is at distance r from point P and r=√x2+a2⟹dV=dq4πϵo√a2+x2⟹V=∫dq=14πϵo√a2+x2∫dq⟹V=Q4πϵo√a2+x2Answer-(D)

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