Find the expression which is equivalent to - x 3 - x 2 - x 4 - x 3-

The correct option is D x ^ 1 The value of x^3+x^2x^4+x^3 = x^2 ( x+1 )x^3 ( x+1 ) = x^2x^3 = x^ 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Division of a Polynomial by a Polynomial

Find the expr...

Question

Find the expression which is equivalent to : $\frac{x^{3} + x^{2}}{x^{4} + x^{3}}$ ?

\frac{x^{5}}{x^{7}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5 x}{7 x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

x_{1}, x_{2}, x_{3}, x_{4}, x_{5}, x_{6}, x_{7}, x_{8}

α

x_{1} < x_{2} < x_{3} < x_{4} < x_{5} < x_{6} < x_{7} < x_{8}

x_{3}, x_{4}, x_{5}, x_{6}

You are given $c o s x = 1 - \frac{x^{2}}{2!} + \frac{x^{4}}{4!} - \frac{x^{6}}{6!} . . . . . .;$

$s i n x = x - \frac{x^{3}}{3!} + \frac{x^{5}}{5!} - \frac{x^{7}}{7!} . . . . . .$

$t a n x = x + \frac{x^{3}}{3} + \frac{2. x^{5}}{15} . . . . . .$

Find the value of $lim x \to 0 \frac{x c o s x + s i n x}{x^{2} + t a n x}$

You are given $c o s x = 1 - \frac{x^{2}}{2!} + \frac{x^{4}}{4!} - \frac{x^{6}}{6!} . . . . . .;$

$s i n x = x - \frac{x^{3}}{3!} + \frac{x^{5}}{5!} - \frac{x^{7}}{7!} . . . . . .$

$t a n x = x + \frac{x^{3}}{3} + \frac{2. x^{5}}{15} . . . . . .$

Find the value of $lim x \to 0 \frac{x c o s x + s i n x}{x^{2} + t a n x}$

\int (x + x^{2} + x^{3} + x^{4})

x \neq - 1

\frac{x^{5} + x^{4} + x^{3} + x^{2}}{x^{3} + x^{2} + x + 1}

Join BYJU'S Learning Program