Find the factor of $6 x^{2} + 17 x + 5$ .

(2 x - 3) (3 x + 1)

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(2 x - 3) (3 x - 1)

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(2 x + 3)^{2}

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(2 x + 3) (3 x + 1)

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Solution

The correct option is D $(2 x + 3) (3 x + 1)$
$6 x^{2} + 17 x + 5$
$= 6 x^{2} + 2 x + 15 x + 5$ (Rewrite $17 x$ as $15 x + 2 x$ to make grouping and factoring easier.)
$= 2 x (3 x + 1) + 3 (3 x + 1)$
$= (2 x + 3) (3 x + 1)$
Therefore $6 x^{2} + 17 x + 5 = (2 x + 3) (3 x + 1)$

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