Question

Find the factor of the polynomial given below.
$\frac{1}{2}{x}^2-3x+4$

Answer 1

$\frac{1}{2}{x}^2-3x+4=\frac{1}{2}{x}^2-2x-x+4$

$=\frac{1}{2}x(x-4)-1(x-4)$

$=(\frac{1}{2}x-1)(x-4)$