Find the factors of $3 m^{2} + 9 m + 6$

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Solution

We have $3 m^{2} + 9 m + 6$

$= 3 m^{2} + 3 m + 6 m + 6$

$= 3 m (m + 1) + 6 (m + 1)$

$= (m + 1) (3 m + 6)$
Hence, the factors of $3 m^{2} + 9 m + 6$ are $(m + 1)$ and $(3 m + 6) .$

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Similar questions

Which of the following is/are the irreducible factor(s) of $3 m^{2} + 9 m + 6 ?$

On factorising $3 m^{2} + 9 m + 6$ , we get the factor(s) as:

3 m^{2} + 9 m + 6

3 m^{2} + 9 m + 6

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