CameraIcon

SearchIcon

MyQuestionIcon

5

You visited us 5 times! Enjoying our articles? Unlock Full Access!

Factorisation by Regrouping Terms

Find the fact...

Question

Find the factors of the following expressions:

(10) 3y³ − 6y² + 4y − 8

Open in App

Solution

3y³ − 6y² + 4y − 8
We can factorise this expression as:
3y³ − 6y² + 4y − 8
= (3y³ − 6y²) + (4y − 8)
= 3y² (y − 2) + 4 (y − 2)
= (y − 2) (3y² + 4)

Suggest Corrections

thumbs-up

0

Similar questions

Q. Add the following polynomials

4 + 2 y - 3 y^{3}, - 8 + 4 y + 7 y^{3}

a n d 5 - 6 y + 8 y^{3} - 6 y^{2}

Q. Find the constant term after adding the following polynomials:

4 + 2 y - 3 y^{3}

- 8 + 4 y + 7 y^{3}

5 - 6 y + 8 y^{3} - 6 y^{2}

Q. Find the factors of the following expressions:

(8) m³ + m² + m + 1

Q. Subtract:
5y⁴− 3y³ + 2y² + y − 1 from 4y⁴ − 2y³ − 6y² − y + 5

{(2 x + 3 y)}^{3} - {(2 x - 3 y)}^{3}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Method of Common Factors

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Factorisation by Regrouping Terms

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon